
Programming FAQ
***************


Contents
^^^^^^^^

* Programming FAQ

  * General Questions

    * Is there a source code level debugger with breakpoints, single-
      stepping, etc.?

    * Is there a tool to help find bugs or perform static analysis?

    * How can I create a stand-alone binary from a Python script?

    * Are there coding standards or a style guide for Python programs?

  * Core Language

    * Why am I getting an UnboundLocalError when the variable has a
      value?

    * What are the rules for local and global variables in Python?

    * Why do lambdas defined in a loop with different values all
      return the same result?

    * How do I share global variables across modules?

    * What are the "best practices" for using import in a module?

    * How can I pass optional or keyword parameters from one function
      to another?

    * What is the difference between arguments and parameters?

    * How do I write a function with output parameters (call by
      reference)?

    * How do you make a higher order function in Python?

    * How do I copy an object in Python?

    * How can I find the methods or attributes of an object?

    * How can my code discover the name of an object?

    * What's up with the comma operator's precedence?

    * Is there an equivalent of C's "?:" ternary operator?

    * Is it possible to write obfuscated one-liners in Python?

  * Numbers and strings

    * How do I specify hexadecimal and octal integers?

    * Why does -22 // 10 return -3?

    * How do I convert a string to a number?

    * How do I convert a number to a string?

    * How do I modify a string in place?

    * How do I use strings to call functions/methods?

    * Is there an equivalent to Perl's chomp() for removing trailing
      newlines from strings?

    * Is there a scanf() or sscanf() equivalent?

    * What does 'UnicodeDecodeError' or 'UnicodeEncodeError' error
      mean?

  * Performance

    * My program is too slow. How do I speed it up?

    * What is the most efficient way to concatenate many strings
      together?

  * Sequences (Tuples/Lists)

    * How do I convert between tuples and lists?

    * What's a negative index?

    * How do I iterate over a sequence in reverse order?

    * How do you remove duplicates from a list?

    * How do you make an array in Python?

    * How do I create a multidimensional list?

    * How do I apply a method to a sequence of objects?

  * Dictionaries

    * How can I get a dictionary to display its keys in a consistent
      order?

    * I want to do a complicated sort: can you do a Schwartzian
      Transform in Python?

    * How can I sort one list by values from another list?

  * Objects

    * What is a class?

    * What is a method?

    * What is self?

    * How do I check if an object is an instance of a given class or
      of a subclass of it?

    * What is delegation?

    * How do I call a method defined in a base class from a derived
      class that overrides it?

    * How can I organize my code to make it easier to change the base
      class?

    * How do I create static class data and static class methods?

    * How can I overload constructors (or methods) in Python?

    * I try to use __spam and I get an error about
      _SomeClassName__spam.

    * My class defines __del__ but it is not called when I delete the
      object.

    * How do I get a list of all instances of a given class?

  * Modules

    * How do I create a .pyc file?

    * How do I find the current module name?

    * How can I have modules that mutually import each other?

    * __import__('x.y.z') returns <module 'x'>; how do I get z?

    * When I edit an imported module and reimport it, the changes
      don't show up.  Why does this happen?


General Questions
=================


Is there a source code level debugger with breakpoints, single-stepping, etc.?
------------------------------------------------------------------------------

Yes.

The pdb module is a simple but adequate console-mode debugger for
Python. It is part of the standard Python library, and is ``documented
in the Library Reference Manual``. You can also write your own
debugger by using the code for pdb as an example.

The IDLE interactive development environment, which is part of the
standard Python distribution (normally available as
Tools/scripts/idle), includes a graphical debugger.  There is
documentation for the IDLE debugger at
http://www.python.org/idle/doc/idle2.html#Debugger.

PythonWin is a Python IDE that includes a GUI debugger based on pdb.
The Pythonwin debugger colors breakpoints and has quite a few cool
features such as debugging non-Pythonwin programs.  Pythonwin is
available as part of the Python for Windows Extensions project and as
a part of the ActivePython distribution (see
http://www.activestate.com/Products/ActivePython/index.html).

Boa Constructor is an IDE and GUI builder that uses wxWidgets.  It
offers visual frame creation and manipulation, an object inspector,
many views on the source like object browsers, inheritance
hierarchies, doc string generated html documentation, an advanced
debugger, integrated help, and Zope support.

Eric is an IDE built on PyQt and the Scintilla editing component.

Pydb is a version of the standard Python debugger pdb, modified for
use with DDD (Data Display Debugger), a popular graphical debugger
front end.  Pydb can be found at http://bashdb.sourceforge.net/pydb/
and DDD can be found at http://www.gnu.org/software/ddd.

There are a number of commercial Python IDEs that include graphical
debuggers. They include:

* Wing IDE (http://wingware.com/)

* Komodo IDE (http://www.activestate.com/Products/Komodo)


Is there a tool to help find bugs or perform static analysis?
-------------------------------------------------------------

Yes.

PyChecker is a static analysis tool that finds bugs in Python source
code and warns about code complexity and style.  You can get PyChecker
from http://pychecker.sf.net.

Pylint is another tool that checks if a module satisfies a coding
standard, and also makes it possible to write plug-ins to add a custom
feature.  In addition to the bug checking that PyChecker performs,
Pylint offers some additional features such as checking line length,
whether variable names are well-formed according to your coding
standard, whether declared interfaces are fully implemented, and more.
http://www.logilab.org/card/pylint_manual provides a full list of
Pylint's features.


How can I create a stand-alone binary from a Python script?
-----------------------------------------------------------

You don't need the ability to compile Python to C code if all you want
is a stand-alone program that users can download and run without
having to install the Python distribution first.  There are a number
of tools that determine the set of modules required by a program and
bind these modules together with a Python binary to produce a single
executable.

One is to use the freeze tool, which is included in the Python source
tree as ``Tools/freeze``. It converts Python byte code to C arrays; a
C compiler you can embed all your modules into a new program, which is
then linked with the standard Python modules.

It works by scanning your source recursively for import statements (in
both forms) and looking for the modules in the standard Python path as
well as in the source directory (for built-in modules).  It then turns
the bytecode for modules written in Python into C code (array
initializers that can be turned into code objects using the marshal
module) and creates a custom-made config file that only contains those
built-in modules which are actually used in the program.  It then
compiles the generated C code and links it with the rest of the Python
interpreter to form a self-contained binary which acts exactly like
your script.

Obviously, freeze requires a C compiler.  There are several other
utilities which don't. One is Thomas Heller's py2exe (Windows only) at

   http://www.py2exe.org/

Another is Christian Tismer's SQFREEZE which appends the byte code to
a specially-prepared Python interpreter that can find the byte code in
the executable.

Other tools include Fredrik Lundh's Squeeze and Anthony Tuininga's
cx_Freeze.


Are there coding standards or a style guide for Python programs?
----------------------------------------------------------------

Yes.  The coding style required for standard library modules is
documented as **PEP 8**.


Core Language
=============


Why am I getting an UnboundLocalError when the variable has a value?
--------------------------------------------------------------------

It can be a surprise to get the UnboundLocalError in previously
working code when it is modified by adding an assignment statement
somewhere in the body of a function.

This code:

>>> x = 10
>>> def bar():
...     print(x)
>>> bar()
10

works, but this code:

>>> x = 10
>>> def foo():
...     print(x)
...     x += 1

results in an UnboundLocalError:

>>> foo()
Traceback (most recent call last):
  ...
UnboundLocalError: local variable 'x' referenced before assignment

This is because when you make an assignment to a variable in a scope,
that variable becomes local to that scope and shadows any similarly
named variable in the outer scope.  Since the last statement in foo
assigns a new value to ``x``, the compiler recognizes it as a local
variable.  Consequently when the earlier ``print(x)`` attempts to
print the uninitialized local variable and an error results.

In the example above you can access the outer scope variable by
declaring it global:

>>> x = 10
>>> def foobar():
...     global x
...     print(x)
...     x += 1
>>> foobar()
10

This explicit declaration is required in order to remind you that
(unlike the superficially analogous situation with class and instance
variables) you are actually modifying the value of the variable in the
outer scope:

>>> print(x)
11

You can do a similar thing in a nested scope using the ``nonlocal``
keyword:

>>> def foo():
...    x = 10
...    def bar():
...        nonlocal x
...        print(x)
...        x += 1
...    bar()
...    print(x)
>>> foo()
10
11


What are the rules for local and global variables in Python?
------------------------------------------------------------

In Python, variables that are only referenced inside a function are
implicitly global.  If a variable is assigned a new value anywhere
within the function's body, it's assumed to be a local.  If a variable
is ever assigned a new value inside the function, the variable is
implicitly local, and you need to explicitly declare it as 'global'.

Though a bit surprising at first, a moment's consideration explains
this.  On one hand, requiring ``global`` for assigned variables
provides a bar against unintended side-effects.  On the other hand, if
``global`` was required for all global references, you'd be using
``global`` all the time.  You'd have to declare as global every
reference to a built-in function or to a component of an imported
module.  This clutter would defeat the usefulness of the ``global``
declaration for identifying side-effects.


Why do lambdas defined in a loop with different values all return the same result?
----------------------------------------------------------------------------------

Assume you use a for loop to define a few different lambdas (or even
plain functions), e.g.:

   squares = []
   for x in range(5):
      squares.append(lambda: x**2)

This gives you a list that contains 5 lambdas that calculate ``x**2``.
You might expect that, when called, they would return, respectively,
``0``, ``1``, ``4``, ``9``, and ``16``.  However, when you actually
try you will see that they all return ``16``:

   >>> squares[2]()
   16
   >>> squares[4]()
   16

This happens because ``x`` is not local to the lambdas, but is defined
in the outer scope, and it is accessed when the lambda is called ---
not when it is defined.  At the end of the loop, the value of ``x`` is
``4``, so all the functions now return ``4**2``, i.e. ``16``.  You can
also verify this by changing the value of ``x`` and see how the
results of the lambdas change:

   >>> x = 8
   >>> squares[2]()
   64

In order to avoid this, you need to save the values in variables local
to the lambdas, so that they don't rely on the value of the global
``x``:

   squares = []
   for x in range(5):
      squares.append(lambda n=x: n**2)

Here, ``n=x`` creates a new variable ``n`` local to the lambda and
computed when the lambda is defined so that it has the same value that
``x`` had at that point in the loop.  This means that the value of
``n`` will be ``0`` in the first lambda, ``1`` in the second, ``2`` in
the third, and so on. Therefore each lambda will now return the
correct result:

   >>> squares[2]()
   4
   >>> squares[4]()
   16

Note that this behaviour is not peculiar to lambdas, but applies to
regular functions too.


How do I share global variables across modules?
-----------------------------------------------

The canonical way to share information across modules within a single
program is to create a special module (often called config or cfg).
Just import the config module in all modules of your application; the
module then becomes available as a global name.  Because there is only
one instance of each module, any changes made to the module object get
reflected everywhere.  For example:

config.py:

   x = 0   # Default value of the 'x' configuration setting

mod.py:

   import config
   config.x = 1

main.py:

   import config
   import mod
   print(config.x)

Note that using a module is also the basis for implementing the
Singleton design pattern, for the same reason.


What are the "best practices" for using import in a module?
-----------------------------------------------------------

In general, don't use ``from modulename import *``.  Doing so clutters
the importer's namespace.  Some people avoid this idiom even with the
few modules that were designed to be imported in this manner.  Modules
designed in this manner include ``tkinter``, and ``threading``.

Import modules at the top of a file.  Doing so makes it clear what
other modules your code requires and avoids questions of whether the
module name is in scope. Using one import per line makes it easy to
add and delete module imports, but using multiple imports per line
uses less screen space.

It's good practice if you import modules in the following order:

1. standard library modules -- e.g. ``sys``, ``os``, ``getopt``,
   ``re``

2. third-party library modules (anything installed in Python's site-
   packages directory) -- e.g. mx.DateTime, ZODB, PIL.Image, etc.

3. locally-developed modules

Never use relative package imports.  If you're writing code that's in
the ``package.sub.m1`` module and want to import ``package.sub.m2``,
do not just write ``from . import m2``, even though it's legal.  Write
``from package.sub import m2`` instead.  See **PEP 328** for details.

It is sometimes necessary to move imports to a function or class to
avoid problems with circular imports.  Gordon McMillan says:

   Circular imports are fine where both modules use the "import
   <module>" form of import.  They fail when the 2nd module wants to
   grab a name out of the first ("from module import name") and the
   import is at the top level.  That's because names in the 1st are
   not yet available, because the first module is busy importing the
   2nd.

In this case, if the second module is only used in one function, then
the import can easily be moved into that function.  By the time the
import is called, the first module will have finished initializing,
and the second module can do its import.

It may also be necessary to move imports out of the top level of code
if some of the modules are platform-specific.  In that case, it may
not even be possible to import all of the modules at the top of the
file.  In this case, importing the correct modules in the
corresponding platform-specific code is a good option.

Only move imports into a local scope, such as inside a function
definition, if it's necessary to solve a problem such as avoiding a
circular import or are trying to reduce the initialization time of a
module.  This technique is especially helpful if many of the imports
are unnecessary depending on how the program executes.  You may also
want to move imports into a function if the modules are only ever used
in that function.  Note that loading a module the first time may be
expensive because of the one time initialization of the module, but
loading a module multiple times is virtually free, costing only a
couple of dictionary lookups.  Even if the module name has gone out of
scope, the module is probably available in ``sys.modules``.

If only instances of a specific class use a module, then it is
reasonable to import the module in the class's ``__init__`` method and
then assign the module to an instance variable so that the module is
always available (via that instance variable) during the life of the
object.  Note that to delay an import until the class is instantiated,
the import must be inside a method.  Putting the import inside the
class but outside of any method still causes the import to occur when
the module is initialized.


How can I pass optional or keyword parameters from one function to another?
---------------------------------------------------------------------------

Collect the arguments using the ``*`` and ``**`` specifiers in the
function's parameter list; this gives you the positional arguments as
a tuple and the keyword arguments as a dictionary.  You can then pass
these arguments when calling another function by using ``*`` and
``**``:

   def f(x, *args, **kwargs):
       ...
       kwargs['width'] = '14.3c'
       ...
       g(x, *args, **kwargs)


What is the difference between arguments and parameters?
--------------------------------------------------------

*Parameters* are defined by the names that appear in a function
definition, whereas *arguments* are the values actually passed to a
function when calling it.  Parameters define what types of arguments a
function can accept.  For example, given the function definition:

   def func(foo, bar=None, **kwargs):
       pass

*foo*, *bar* and *kwargs* are parameters of ``func``.  However, when
calling ``func``, for example:

   func(42, bar=314, extra=somevar)

the values ``42``, ``314``, and ``somevar`` are arguments.


How do I write a function with output parameters (call by reference)?
---------------------------------------------------------------------

Remember that arguments are passed by assignment in Python.  Since
assignment just creates references to objects, there's no alias
between an argument name in the caller and callee, and so no call-by-
reference per se.  You can achieve the desired effect in a number of
ways.

1. By returning a tuple of the results:

      def func2(a, b):
          a = 'new-value'        # a and b are local names
          b = b + 1              # assigned to new objects
          return a, b            # return new values

      x, y = 'old-value', 99
      x, y = func2(x, y)
      print(x, y)                # output: new-value 100

   This is almost always the clearest solution.

2. By using global variables.  This isn't thread-safe, and is not
   recommended.

3. By passing a mutable (changeable in-place) object:

      def func1(a):
          a[0] = 'new-value'     # 'a' references a mutable list
          a[1] = a[1] + 1        # changes a shared object

      args = ['old-value', 99]
      func1(args)
      print(args[0], args[1])    # output: new-value 100

4. By passing in a dictionary that gets mutated:

      def func3(args):
          args['a'] = 'new-value'     # args is a mutable dictionary
          args['b'] = args['b'] + 1   # change it in-place

      args = {'a':' old-value', 'b': 99}
      func3(args)
      print(args['a'], args['b'])

5. Or bundle up values in a class instance:

      class callByRef:
          def __init__(self, **args):
              for (key, value) in args.items():
                  setattr(self, key, value)

      def func4(args):
          args.a = 'new-value'        # args is a mutable callByRef
          args.b = args.b + 1         # change object in-place

      args = callByRef(a='old-value', b=99)
      func4(args)
      print(args.a, args.b)

   There's almost never a good reason to get this complicated.

Your best choice is to return a tuple containing the multiple results.


How do you make a higher order function in Python?
--------------------------------------------------

You have two choices: you can use nested scopes or you can use
callable objects. For example, suppose you wanted to define
``linear(a,b)`` which returns a function ``f(x)`` that computes the
value ``a*x+b``.  Using nested scopes:

   def linear(a, b):
       def result(x):
           return a * x + b
       return result

Or using a callable object:

   class linear:

       def __init__(self, a, b):
           self.a, self.b = a, b

       def __call__(self, x):
           return self.a * x + self.b

In both cases,

   taxes = linear(0.3, 2)

gives a callable object where ``taxes(10e6) == 0.3 * 10e6 + 2``.

The callable object approach has the disadvantage that it is a bit
slower and results in slightly longer code.  However, note that a
collection of callables can share their signature via inheritance:

   class exponential(linear):
       # __init__ inherited
       def __call__(self, x):
           return self.a * (x ** self.b)

Object can encapsulate state for several methods:

   class counter:

       value = 0

       def set(self, x):
           self.value = x

       def up(self):
           self.value = self.value + 1

       def down(self):
           self.value = self.value - 1

   count = counter()
   inc, dec, reset = count.up, count.down, count.set

Here ``inc()``, ``dec()`` and ``reset()`` act like functions which
share the same counting variable.


How do I copy an object in Python?
----------------------------------

In general, try ``copy.copy()`` or ``copy.deepcopy()`` for the general
case. Not all objects can be copied, but most can.

Some objects can be copied more easily.  Dictionaries have a
``copy()`` method:

   newdict = olddict.copy()

Sequences can be copied by slicing:

   new_l = l[:]


How can I find the methods or attributes of an object?
------------------------------------------------------

For an instance x of a user-defined class, ``dir(x)`` returns an
alphabetized list of the names containing the instance attributes and
methods and attributes defined by its class.


How can my code discover the name of an object?
-----------------------------------------------

Generally speaking, it can't, because objects don't really have names.
Essentially, assignment always binds a name to a value; The same is
true of ``def`` and ``class`` statements, but in that case the value
is a callable. Consider the following code:

   class A:
       pass

   B = A

   a = B()
   b = a
   print(b)
   <__main__.A object at 0x16D07CC>
   print(a)
   <__main__.A object at 0x16D07CC>

Arguably the class has a name: even though it is bound to two names
and invoked through the name B the created instance is still reported
as an instance of class A.  However, it is impossible to say whether
the instance's name is a or b, since both names are bound to the same
value.

Generally speaking it should not be necessary for your code to "know
the names" of particular values. Unless you are deliberately writing
introspective programs, this is usually an indication that a change of
approach might be beneficial.

In comp.lang.python, Fredrik Lundh once gave an excellent analogy in
answer to this question:

   The same way as you get the name of that cat you found on your
   porch: the cat (object) itself cannot tell you its name, and it
   doesn't really care -- so the only way to find out what it's called
   is to ask all your neighbours (namespaces) if it's their cat
   (object)...

   ....and don't be surprised if you'll find that it's known by many
   names, or no name at all!


What's up with the comma operator's precedence?
-----------------------------------------------

Comma is not an operator in Python.  Consider this session:

   >>> "a" in "b", "a"
   (False, 'a')

Since the comma is not an operator, but a separator between
expressions the above is evaluated as if you had entered:

   >>> ("a" in "b"), "a"

not:

   >>> "a" in ("b", "a")

The same is true of the various assignment operators (``=``, ``+=``
etc).  They are not truly operators but syntactic delimiters in
assignment statements.


Is there an equivalent of C's "?:" ternary operator?
----------------------------------------------------

Yes, there is. The syntax is as follows:

   [on_true] if [expression] else [on_false]

   x, y = 50, 25
   small = x if x < y else y

Before this syntax was introduced in Python 2.5, a common idiom was to
use logical operators:

   [expression] and [on_true] or [on_false]

However, this idiom is unsafe, as it can give wrong results when
*on_true* has a false boolean value.  Therefore, it is always better
to use the ``... if ... else ...`` form.


Is it possible to write obfuscated one-liners in Python?
--------------------------------------------------------

Yes.  Usually this is done by nesting ``lambda`` within ``lambda``.
See the following three examples, due to Ulf Bartelt:

   from functools import reduce

   # Primes < 1000
   print(list(filter(None,map(lambda y:y*reduce(lambda x,y:x*y!=0,
   map(lambda x,y=y:y%x,range(2,int(pow(y,0.5)+1))),1),range(2,1000)))))

   # First 10 Fibonacci numbers
   print(list(map(lambda x,f=lambda x,f:(f(x-1,f)+f(x-2,f)) if x>1 else 1:
   f(x,f), range(10))))

   # Mandelbrot set
   print((lambda Ru,Ro,Iu,Io,IM,Sx,Sy:reduce(lambda x,y:x+y,map(lambda y,
   Iu=Iu,Io=Io,Ru=Ru,Ro=Ro,Sy=Sy,L=lambda yc,Iu=Iu,Io=Io,Ru=Ru,Ro=Ro,i=IM,
   Sx=Sx,Sy=Sy:reduce(lambda x,y:x+y,map(lambda x,xc=Ru,yc=yc,Ru=Ru,Ro=Ro,
   i=i,Sx=Sx,F=lambda xc,yc,x,y,k,f=lambda xc,yc,x,y,k,f:(k<=0)or (x*x+y*y
   >=4.0) or 1+f(xc,yc,x*x-y*y+xc,2.0*x*y+yc,k-1,f):f(xc,yc,x,y,k,f):chr(
   64+F(Ru+x*(Ro-Ru)/Sx,yc,0,0,i)),range(Sx))):L(Iu+y*(Io-Iu)/Sy),range(Sy
   ))))(-2.1, 0.7, -1.2, 1.2, 30, 80, 24))
   #    \___ ___/  \___ ___/  |   |   |__ lines on screen
   #        V          V      |   |______ columns on screen
   #        |          |      |__________ maximum of "iterations"
   #        |          |_________________ range on y axis
   #        |____________________________ range on x axis

Don't try this at home, kids!


Numbers and strings
===================


How do I specify hexadecimal and octal integers?
------------------------------------------------

To specify an octal digit, precede the octal value with a zero, and
then a lower or uppercase "o".  For example, to set the variable "a"
to the octal value "10" (8 in decimal), type:

   >>> a = 0o10
   >>> a
   8

Hexadecimal is just as easy.  Simply precede the hexadecimal number
with a zero, and then a lower or uppercase "x".  Hexadecimal digits
can be specified in lower or uppercase.  For example, in the Python
interpreter:

   >>> a = 0xa5
   >>> a
   165
   >>> b = 0XB2
   >>> b
   178


Why does -22 // 10 return -3?
-----------------------------

It's primarily driven by the desire that ``i % j`` have the same sign
as ``j``. If you want that, and also want:

   i == (i // j) * j + (i % j)

then integer division has to return the floor.  C also requires that
identity to hold, and then compilers that truncate ``i // j`` need to
make ``i % j`` have the same sign as ``i``.

There are few real use cases for ``i % j`` when ``j`` is negative.
When ``j`` is positive, there are many, and in virtually all of them
it's more useful for ``i % j`` to be ``>= 0``.  If the clock says 10
now, what did it say 200 hours ago?  ``-190 % 12 == 2`` is useful;
``-190 % 12 == -10`` is a bug waiting to bite.


How do I convert a string to a number?
--------------------------------------

For integers, use the built-in ``int()`` type constructor, e.g.
``int('144') == 144``.  Similarly, ``float()`` converts to floating-
point, e.g. ``float('144') == 144.0``.

By default, these interpret the number as decimal, so that
``int('0144') == 144`` and ``int('0x144')`` raises ``ValueError``.
``int(string, base)`` takes the base to convert from as a second
optional argument, so ``int('0x144', 16) == 324``.  If the base is
specified as 0, the number is interpreted using Python's rules: a
leading '0' indicates octal, and '0x' indicates a hex number.

Do not use the built-in function ``eval()`` if all you need is to
convert strings to numbers.  ``eval()`` will be significantly slower
and it presents a security risk: someone could pass you a Python
expression that might have unwanted side effects.  For example,
someone could pass ``__import__('os').system("rm -rf $HOME")`` which
would erase your home directory.

``eval()`` also has the effect of interpreting numbers as Python
expressions, so that e.g. ``eval('09')`` gives a syntax error because
Python does not allow leading '0' in a decimal number (except '0').


How do I convert a number to a string?
--------------------------------------

To convert, e.g., the number 144 to the string '144', use the built-in
type constructor ``str()``.  If you want a hexadecimal or octal
representation, use the built-in functions ``hex()`` or ``oct()``.
For fancy formatting, see the *String Formatting* section, e.g.
``"{:04d}".format(144)`` yields ``'0144'`` and
``"{:.3f}".format(1/3)`` yields ``'0.333'``.


How do I modify a string in place?
----------------------------------

You can't, because strings are immutable.  In most situations, you
should simply construct a new string from the various parts you want
to assemble it from.  However, if you need an object with the ability
to modify in-place unicode data, try using a ``io.StringIO`` object or
the ``array`` module:

   >>> s = "Hello, world"
   >>> sio = io.StringIO(s)
   >>> sio.getvalue()
   'Hello, world'
   >>> sio.seek(7)
   7
   >>> sio.write("there!")
   6
   >>> sio.getvalue()
   'Hello, there!'

   >>> import array
   >>> a = array.array('u', s)
   >>> print(a)
   array('u', 'Hello, world')
   >>> a[0] = 'y'
   >>> print(a)
   array('u', 'yello world')
   >>> a.tounicode()
   'yello, world'


How do I use strings to call functions/methods?
-----------------------------------------------

There are various techniques.

* The best is to use a dictionary that maps strings to functions.  The
  primary advantage of this technique is that the strings do not need
  to match the names of the functions.  This is also the primary
  technique used to emulate a case construct:

     def a():
         pass

     def b():
         pass

     dispatch = {'go': a, 'stop': b}  # Note lack of parens for funcs

     dispatch[get_input()]()  # Note trailing parens to call function

* Use the built-in function ``getattr()``:

     import foo
     getattr(foo, 'bar')()

  Note that ``getattr()`` works on any object, including classes,
  class instances, modules, and so on.

  This is used in several places in the standard library, like this:

     class Foo:
         def do_foo(self):
             ...

         def do_bar(self):
             ...

     f = getattr(foo_instance, 'do_' + opname)
     f()

* Use ``locals()`` or ``eval()`` to resolve the function name:

     def myFunc():
         print("hello")

     fname = "myFunc"

     f = locals()[fname]
     f()

     f = eval(fname)
     f()

  Note: Using ``eval()`` is slow and dangerous.  If you don't have
  absolute control over the contents of the string, someone could pass
  a string that resulted in an arbitrary function being executed.


Is there an equivalent to Perl's chomp() for removing trailing newlines from strings?
-------------------------------------------------------------------------------------

You can use ``S.rstrip("\r\n")`` to remove all occurrences of any line
terminator from the end of the string ``S`` without removing other
trailing whitespace.  If the string ``S`` represents more than one
line, with several empty lines at the end, the line terminators for
all the blank lines will be removed:

   >>> lines = ("line 1 \r\n"
   ...          "\r\n"
   ...          "\r\n")
   >>> lines.rstrip("\n\r")
   'line 1 '

Since this is typically only desired when reading text one line at a
time, using ``S.rstrip()`` this way works well.


Is there a scanf() or sscanf() equivalent?
------------------------------------------

Not as such.

For simple input parsing, the easiest approach is usually to split the
line into whitespace-delimited words using the ``split()`` method of
string objects and then convert decimal strings to numeric values
using ``int()`` or ``float()``.  ``split()`` supports an optional
"sep" parameter which is useful if the line uses something other than
whitespace as a separator.

For more complicated input parsing, regular expressions are more
powerful than C's ``sscanf()`` and better suited for the task.


What does 'UnicodeDecodeError' or 'UnicodeEncodeError' error  mean?
-------------------------------------------------------------------

See the *Unicode HOWTO*.


Performance
===========


My program is too slow. How do I speed it up?
---------------------------------------------

That's a tough one, in general.  First, here are a list of things to
remember before diving further:

* Performance characteristics vary across Python implementations.
  This FAQ focusses on *CPython*.

* Behaviour can vary across operating systems, especially when talking
  about I/O or multi-threading.

* You should always find the hot spots in your program *before*
  attempting to optimize any code (see the ``profile`` module).

* Writing benchmark scripts will allow you to iterate quickly when
  searching for improvements (see the ``timeit`` module).

* It is highly recommended to have good code coverage (through unit
  testing or any other technique) before potentially introducing
  regressions hidden in sophisticated optimizations.

That being said, there are many tricks to speed up Python code.  Here
are some general principles which go a long way towards reaching
acceptable performance levels:

* Making your algorithms faster (or changing to faster ones) can yield
  much larger benefits than trying to sprinkle micro-optimization
  tricks all over your code.

* Use the right data structures.  Study documentation for the *Built-
  in Types* and the ``collections`` module.

* When the standard library provides a primitive for doing something,
  it is likely (although not guaranteed) to be faster than any
  alternative you may come up with.  This is doubly true for
  primitives written in C, such as builtins and some extension types.
  For example, be sure to use either the ``list.sort()`` built-in
  method or the related ``sorted()`` function to do sorting (and see
  the sorting mini-HOWTO for examples of moderately advanced usage).

* Abstractions tend to create indirections and force the interpreter
  to work more.  If the levels of indirection outweigh the amount of
  useful work done, your program will be slower.  You should avoid
  excessive abstraction, especially under the form of tiny functions
  or methods (which are also often detrimental to readability).

If you have reached the limit of what pure Python can allow, there are
tools to take you further away.  For example, Cython can compile a
slightly modified version of Python code into a C extension, and can
be used on many different platforms.  Cython can take advantage of
compilation (and optional type annotations) to make your code
significantly faster than when interpreted.  If you are confident in
your C programming skills, you can also *write a C extension module*
yourself.

See also:

   The wiki page devoted to performance tips.


What is the most efficient way to concatenate many strings together?
--------------------------------------------------------------------

``str`` and ``bytes`` objects are immutable, therefore concatenating
many strings together is inefficient as each concatenation creates a
new object.  In the general case, the total runtime cost is quadratic
in the total string length.

To accumulate many ``str`` objects, the recommended idiom is to place
them into a list and call ``str.join()`` at the end:

   chunks = []
   for s in my_strings:
       chunks.append(s)
   result = ''.join(chunks)

(another reasonably efficient idiom is to use ``io.StringIO``)

To accumulate many ``bytes`` objects, the recommended idiom is to
extend a ``bytearray`` object using in-place concatenation (the ``+=``
operator):

   result = bytearray()
   for b in my_bytes_objects:
       result += b


Sequences (Tuples/Lists)
========================


How do I convert between tuples and lists?
------------------------------------------

The type constructor ``tuple(seq)`` converts any sequence (actually,
any iterable) into a tuple with the same items in the same order.

For example, ``tuple([1, 2, 3])`` yields ``(1, 2, 3)`` and
``tuple('abc')`` yields ``('a', 'b', 'c')``.  If the argument is a
tuple, it does not make a copy but returns the same object, so it is
cheap to call ``tuple()`` when you aren't sure that an object is
already a tuple.

The type constructor ``list(seq)`` converts any sequence or iterable
into a list with the same items in the same order.  For example,
``list((1, 2, 3))`` yields ``[1, 2, 3]`` and ``list('abc')`` yields
``['a', 'b', 'c']``.  If the argument is a list, it makes a copy just
like ``seq[:]`` would.


What's a negative index?
------------------------

Python sequences are indexed with positive numbers and negative
numbers.  For positive numbers 0 is the first index 1 is the second
index and so forth.  For negative indices -1 is the last index and -2
is the penultimate (next to last) index and so forth.  Think of
``seq[-n]`` as the same as ``seq[len(seq)-n]``.

Using negative indices can be very convenient.  For example ``S[:-1]``
is all of the string except for its last character, which is useful
for removing the trailing newline from a string.


How do I iterate over a sequence in reverse order?
--------------------------------------------------

Use the ``reversed()`` built-in function, which is new in Python 2.4:

   for x in reversed(sequence):
       ... # do something with x...

This won't touch your original sequence, but build a new copy with
reversed order to iterate over.

With Python 2.3, you can use an extended slice syntax:

   for x in sequence[::-1]:
       ... # do something with x...


How do you remove duplicates from a list?
-----------------------------------------

See the Python Cookbook for a long discussion of many ways to do this:

   http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/52560

If you don't mind reordering the list, sort it and then scan from the
end of the list, deleting duplicates as you go:

   if mylist:
       mylist.sort()
       last = mylist[-1]
       for i in range(len(mylist)-2, -1, -1):
           if last == mylist[i]:
               del mylist[i]
           else:
               last = mylist[i]

If all elements of the list may be used as set keys (i.e. they are all
*hashable*) this is often faster

   mylist = list(set(mylist))

This converts the list into a set, thereby removing duplicates, and
then back into a list.


How do you make an array in Python?
-----------------------------------

Use a list:

   ["this", 1, "is", "an", "array"]

Lists are equivalent to C or Pascal arrays in their time complexity;
the primary difference is that a Python list can contain objects of
many different types.

The ``array`` module also provides methods for creating arrays of
fixed types with compact representations, but they are slower to index
than lists.  Also note that the Numeric extensions and others define
array-like structures with various characteristics as well.

To get Lisp-style linked lists, you can emulate cons cells using
tuples:

   lisp_list = ("like",  ("this",  ("example", None) ) )

If mutability is desired, you could use lists instead of tuples.  Here
the analogue of lisp car is ``lisp_list[0]`` and the analogue of cdr
is ``lisp_list[1]``.  Only do this if you're sure you really need to,
because it's usually a lot slower than using Python lists.


How do I create a multidimensional list?
----------------------------------------

You probably tried to make a multidimensional array like this:

   A = [[None] * 2] * 3

This looks correct if you print it:

   >>> A
   [[None, None], [None, None], [None, None]]

But when you assign a value, it shows up in multiple places:

>>> A[0][0] = 5
>>> A
[[5, None], [5, None], [5, None]]

The reason is that replicating a list with ``*`` doesn't create
copies, it only creates references to the existing objects.  The
``*3`` creates a list containing 3 references to the same list of
length two.  Changes to one row will show in all rows, which is almost
certainly not what you want.

The suggested approach is to create a list of the desired length first
and then fill in each element with a newly created list:

   A = [None] * 3
   for i in range(3):
       A[i] = [None] * 2

This generates a list containing 3 different lists of length two.  You
can also use a list comprehension:

   w, h = 2, 3
   A = [[None] * w for i in range(h)]

Or, you can use an extension that provides a matrix datatype; Numeric
Python is the best known.


How do I apply a method to a sequence of objects?
-------------------------------------------------

Use a list comprehension:

   result = [obj.method() for obj in mylist]


Dictionaries
============


How can I get a dictionary to display its keys in a consistent order?
---------------------------------------------------------------------

You can't.  Dictionaries store their keys in an unpredictable order,
so the display order of a dictionary's elements will be similarly
unpredictable.

This can be frustrating if you want to save a printable version to a
file, make some changes and then compare it with some other printed
dictionary.  In this case, use the ``pprint`` module to pretty-print
the dictionary; the items will be presented in order sorted by the
key.

A more complicated solution is to subclass ``dict`` to create a
``SortedDict`` class that prints itself in a predictable order.
Here's one simpleminded implementation of such a class:

   class SortedDict(dict):
       def __repr__(self):
           keys = sorted(self.keys())
           result = ("{!r}: {!r}".format(k, self[k]) for k in keys)
           return "{{{}}}".format(", ".join(result))

       __str__ = __repr__

This will work for many common situations you might encounter, though
it's far from a perfect solution. The largest flaw is that if some
values in the dictionary are also dictionaries, their values won't be
presented in any particular order.


I want to do a complicated sort: can you do a Schwartzian Transform in Python?
------------------------------------------------------------------------------

The technique, attributed to Randal Schwartz of the Perl community,
sorts the elements of a list by a metric which maps each element to
its "sort value". In Python, just use the ``key`` argument for the
``sort()`` method:

   Isorted = L[:]
   Isorted.sort(key=lambda s: int(s[10:15]))

The ``key`` argument is new in Python 2.4, for older versions this
kind of sorting is quite simple to do with list comprehensions.  To
sort a list of strings by their uppercase values:

   tmp1 = [(x.upper(), x) for x in L]  # Schwartzian transform
   tmp1.sort()
   Usorted = [x[1] for x in tmp1]

To sort by the integer value of a subfield extending from positions
10-15 in each string:

   tmp2 = [(int(s[10:15]), s) for s in L]  # Schwartzian transform
   tmp2.sort()
   Isorted = [x[1] for x in tmp2]

For versions prior to 3.0, Isorted may also be computed by

   def intfield(s):
       return int(s[10:15])

   def Icmp(s1, s2):
       return cmp(intfield(s1), intfield(s2))

   Isorted = L[:]
   Isorted.sort(Icmp)

but since this method calls ``intfield()`` many times for each element
of L, it is slower than the Schwartzian Transform.


How can I sort one list by values from another list?
----------------------------------------------------

Merge them into an iterator of tuples, sort the resulting list, and
then pick out the element you want.

   >>> list1 = ["what", "I'm", "sorting", "by"]
   >>> list2 = ["something", "else", "to", "sort"]
   >>> pairs = zip(list1, list2)
   >>> pairs = sorted(pairs)
   >>> pairs
   [("I'm", 'else'), ('by', 'sort'), ('sorting', 'to'), ('what', 'something')]
   >>> result = [x[1] for x in pairs]
   >>> result
   ['else', 'sort', 'to', 'something']

An alternative for the last step is:

   >>> result = []
   >>> for p in pairs: result.append(p[1])

If you find this more legible, you might prefer to use this instead of
the final list comprehension.  However, it is almost twice as slow for
long lists.  Why? First, the ``append()`` operation has to reallocate
memory, and while it uses some tricks to avoid doing that each time,
it still has to do it occasionally, and that costs quite a bit.
Second, the expression "result.append" requires an extra attribute
lookup, and third, there's a speed reduction from having to make all
those function calls.


Objects
=======


What is a class?
----------------

A class is the particular object type created by executing a class
statement. Class objects are used as templates to create instance
objects, which embody both the data (attributes) and code (methods)
specific to a datatype.

A class can be based on one or more other classes, called its base
class(es). It then inherits the attributes and methods of its base
classes. This allows an object model to be successively refined by
inheritance.  You might have a generic ``Mailbox`` class that provides
basic accessor methods for a mailbox, and subclasses such as
``MboxMailbox``, ``MaildirMailbox``, ``OutlookMailbox`` that handle
various specific mailbox formats.


What is a method?
-----------------

A method is a function on some object ``x`` that you normally call as
``x.name(arguments...)``.  Methods are defined as functions inside the
class definition:

   class C:
       def meth (self, arg):
           return arg * 2 + self.attribute


What is self?
-------------

Self is merely a conventional name for the first argument of a method.
A method defined as ``meth(self, a, b, c)`` should be called as
``x.meth(a, b, c)`` for some instance ``x`` of the class in which the
definition occurs; the called method will think it is called as
``meth(x, a, b, c)``.

See also *Why must 'self' be used explicitly in method definitions and
calls?*.


How do I check if an object is an instance of a given class or of a subclass of it?
-----------------------------------------------------------------------------------

Use the built-in function ``isinstance(obj, cls)``.  You can check if
an object is an instance of any of a number of classes by providing a
tuple instead of a single class, e.g. ``isinstance(obj, (class1,
class2, ...))``, and can also check whether an object is one of
Python's built-in types, e.g. ``isinstance(obj, str)`` or
``isinstance(obj, (int, float, complex))``.

Note that most programs do not use ``isinstance()`` on user-defined
classes very often.  If you are developing the classes yourself, a
more proper object-oriented style is to define methods on the classes
that encapsulate a particular behaviour, instead of checking the
object's class and doing a different thing based on what class it is.
For example, if you have a function that does something:

   def search(obj):
       if isinstance(obj, Mailbox):
           # ... code to search a mailbox
       elif isinstance(obj, Document):
           # ... code to search a document
       elif ...

A better approach is to define a ``search()`` method on all the
classes and just call it:

   class Mailbox:
       def search(self):
           # ... code to search a mailbox

   class Document:
       def search(self):
           # ... code to search a document

   obj.search()


What is delegation?
-------------------

Delegation is an object oriented technique (also called a design
pattern). Let's say you have an object ``x`` and want to change the
behaviour of just one of its methods.  You can create a new class that
provides a new implementation of the method you're interested in
changing and delegates all other methods to the corresponding method
of ``x``.

Python programmers can easily implement delegation.  For example, the
following class implements a class that behaves like a file but
converts all written data to uppercase:

   class UpperOut:

       def __init__(self, outfile):
           self._outfile = outfile

       def write(self, s):
           self._outfile.write(s.upper())

       def __getattr__(self, name):
           return getattr(self._outfile, name)

Here the ``UpperOut`` class redefines the ``write()`` method to
convert the argument string to uppercase before calling the underlying
``self.__outfile.write()`` method.  All other methods are delegated to
the underlying ``self.__outfile`` object.  The delegation is
accomplished via the ``__getattr__`` method; consult *the language
reference* for more information about controlling attribute access.

Note that for more general cases delegation can get trickier. When
attributes must be set as well as retrieved, the class must define a
``__setattr__()`` method too, and it must do so carefully.  The basic
implementation of ``__setattr__()`` is roughly equivalent to the
following:

   class X:
       ...
       def __setattr__(self, name, value):
           self.__dict__[name] = value
       ...

Most ``__setattr__()`` implementations must modify ``self.__dict__``
to store local state for self without causing an infinite recursion.


How do I call a method defined in a base class from a derived class that overrides it?
--------------------------------------------------------------------------------------

Use the built-in ``super()`` function:

   class Derived(Base):
       def meth (self):
           super(Derived, self).meth()

For version prior to 3.0, you may be using classic classes: For a
class definition such as ``class Derived(Base): ...`` you can call
method ``meth()`` defined in ``Base`` (or one of ``Base``'s base
classes) as ``Base.meth(self, arguments...)``.  Here, ``Base.meth`` is
an unbound method, so you need to provide the ``self`` argument.


How can I organize my code to make it easier to change the base class?
----------------------------------------------------------------------

You could define an alias for the base class, assign the real base
class to it before your class definition, and use the alias throughout
your class.  Then all you have to change is the value assigned to the
alias.  Incidentally, this trick is also handy if you want to decide
dynamically (e.g. depending on availability of resources) which base
class to use.  Example:

   BaseAlias = <real base class>

   class Derived(BaseAlias):
       def meth(self):
           BaseAlias.meth(self)
           ...


How do I create static class data and static class methods?
-----------------------------------------------------------

Both static data and static methods (in the sense of C++ or Java) are
supported in Python.

For static data, simply define a class attribute.  To assign a new
value to the attribute, you have to explicitly use the class name in
the assignment:

   class C:
       count = 0   # number of times C.__init__ called

       def __init__(self):
           C.count = C.count + 1

       def getcount(self):
           return C.count  # or return self.count

``c.count`` also refers to ``C.count`` for any ``c`` such that
``isinstance(c, C)`` holds, unless overridden by ``c`` itself or by
some class on the base-class search path from ``c.__class__`` back to
``C``.

Caution: within a method of C, an assignment like ``self.count = 42``
creates a new and unrelated instance named "count" in ``self``'s own
dict.  Rebinding of a class-static data name must always specify the
class whether inside a method or not:

   C.count = 314

Static methods are possible:

   class C:
       @staticmethod
       def static(arg1, arg2, arg3):
           # No 'self' parameter!
           ...

However, a far more straightforward way to get the effect of a static
method is via a simple module-level function:

   def getcount():
       return C.count

If your code is structured so as to define one class (or tightly
related class hierarchy) per module, this supplies the desired
encapsulation.


How can I overload constructors (or methods) in Python?
-------------------------------------------------------

This answer actually applies to all methods, but the question usually
comes up first in the context of constructors.

In C++ you'd write

   class C {
       C() { cout << "No arguments\n"; }
       C(int i) { cout << "Argument is " << i << "\n"; }
   }

In Python you have to write a single constructor that catches all
cases using default arguments.  For example:

   class C:
       def __init__(self, i=None):
           if i is None:
               print("No arguments")
           else:
               print("Argument is", i)

This is not entirely equivalent, but close enough in practice.

You could also try a variable-length argument list, e.g.

   def __init__(self, *args):
       ...

The same approach works for all method definitions.


I try to use __spam and I get an error about _SomeClassName__spam.
------------------------------------------------------------------

Variable names with double leading underscores are "mangled" to
provide a simple but effective way to define class private variables.
Any identifier of the form ``__spam`` (at least two leading
underscores, at most one trailing underscore) is textually replaced
with ``_classname__spam``, where ``classname`` is the current class
name with any leading underscores stripped.

This doesn't guarantee privacy: an outside user can still deliberately
access the "_classname__spam" attribute, and private values are
visible in the object's ``__dict__``.  Many Python programmers never
bother to use private variable names at all.


My class defines __del__ but it is not called when I delete the object.
-----------------------------------------------------------------------

There are several possible reasons for this.

The del statement does not necessarily call ``__del__()`` -- it simply
decrements the object's reference count, and if this reaches zero
``__del__()`` is called.

If your data structures contain circular links (e.g. a tree where each
child has a parent reference and each parent has a list of children)
the reference counts will never go back to zero.  Once in a while
Python runs an algorithm to detect such cycles, but the garbage
collector might run some time after the last reference to your data
structure vanishes, so your ``__del__()`` method may be called at an
inconvenient and random time. This is inconvenient if you're trying to
reproduce a problem. Worse, the order in which object's ``__del__()``
methods are executed is arbitrary.  You can run ``gc.collect()`` to
force a collection, but there *are* pathological cases where objects
will never be collected.

Despite the cycle collector, it's still a good idea to define an
explicit ``close()`` method on objects to be called whenever you're
done with them.  The ``close()`` method can then remove attributes
that refer to subobjecs.  Don't call ``__del__()`` directly --
``__del__()`` should call ``close()`` and ``close()`` should make sure
that it can be called more than once for the same object.

Another way to avoid cyclical references is to use the ``weakref``
module, which allows you to point to objects without incrementing
their reference count. Tree data structures, for instance, should use
weak references for their parent and sibling references (if they need
them!).

Finally, if your ``__del__()`` method raises an exception, a warning
message is printed to ``sys.stderr``.


How do I get a list of all instances of a given class?
------------------------------------------------------

Python does not keep track of all instances of a class (or of a built-
in type). You can program the class's constructor to keep track of all
instances by keeping a list of weak references to each instance.


Modules
=======


How do I create a .pyc file?
----------------------------

When a module is imported for the first time (or when the source is
more recent than the current compiled file) a ``.pyc`` file containing
the compiled code should be created in the same directory as the
``.py`` file.

One reason that a ``.pyc`` file may not be created is permissions
problems with the directory. This can happen, for example, if you
develop as one user but run as another, such as if you are testing
with a web server.  Creation of a .pyc file is automatic if you're
importing a module and Python has the ability (permissions, free
space, etc...) to write the compiled module back to the directory.

Running Python on a top level script is not considered an import and
no ``.pyc`` will be created.  For example, if you have a top-level
module ``abc.py`` that imports another module ``xyz.py``, when you run
abc, ``xyz.pyc`` will be created since xyz is imported, but no
``abc.pyc`` file will be created since ``abc.py`` isn't being
imported.

If you need to create abc.pyc -- that is, to create a .pyc file for a
module that is not imported -- you can, using the ``py_compile`` and
``compileall`` modules.

The ``py_compile`` module can manually compile any module.  One way is
to use the ``compile()`` function in that module interactively:

   >>> import py_compile
   >>> py_compile.compile('abc.py')

This will write the ``.pyc`` to the same location as ``abc.py`` (or
you can override that with the optional parameter ``cfile``).

You can also automatically compile all files in a directory or
directories using the ``compileall`` module.  You can do it from the
shell prompt by running ``compileall.py`` and providing the path of a
directory containing Python files to compile:

   python -m compileall .


How do I find the current module name?
--------------------------------------

A module can find out its own module name by looking at the predefined
global variable ``__name__``.  If this has the value ``'__main__'``,
the program is running as a script.  Many modules that are usually
used by importing them also provide a command-line interface or a
self-test, and only execute this code after checking ``__name__``:

   def main():
       print('Running test...')
       ...

   if __name__ == '__main__':
       main()


How can I have modules that mutually import each other?
-------------------------------------------------------

Suppose you have the following modules:

foo.py:

   from bar import bar_var
   foo_var = 1

bar.py:

   from foo import foo_var
   bar_var = 2

The problem is that the interpreter will perform the following steps:

* main imports foo

* Empty globals for foo are created

* foo is compiled and starts executing

* foo imports bar

* Empty globals for bar are created

* bar is compiled and starts executing

* bar imports foo (which is a no-op since there already is a module
  named foo)

* bar.foo_var = foo.foo_var

The last step fails, because Python isn't done with interpreting
``foo`` yet and the global symbol dictionary for ``foo`` is still
empty.

The same thing happens when you use ``import foo``, and then try to
access ``foo.foo_var`` in global code.

There are (at least) three possible workarounds for this problem.

Guido van Rossum recommends avoiding all uses of ``from <module>
import ...``, and placing all code inside functions.  Initializations
of global variables and class variables should use constants or built-
in functions only.  This means everything from an imported module is
referenced as ``<module>.<name>``.

Jim Roskind suggests performing steps in the following order in each
module:

* exports (globals, functions, and classes that don't need imported
  base classes)

* ``import`` statements

* active code (including globals that are initialized from imported
  values).

van Rossum doesn't like this approach much because the imports appear
in a strange place, but it does work.

Matthias Urlichs recommends restructuring your code so that the
recursive import is not necessary in the first place.

These solutions are not mutually exclusive.


__import__('x.y.z') returns <module 'x'>; how do I get z?
---------------------------------------------------------

Try:

   __import__('x.y.z').y.z

For more realistic situations, you may have to do something like

   m = __import__(s)
   for i in s.split(".")[1:]:
       m = getattr(m, i)

See ``importlib`` for a convenience function called
``import_module()``.


When I edit an imported module and reimport it, the changes don't show up.  Why does this happen?
-------------------------------------------------------------------------------------------------

For reasons of efficiency as well as consistency, Python only reads
the module file on the first time a module is imported.  If it didn't,
in a program consisting of many modules where each one imports the
same basic module, the basic module would be parsed and re-parsed many
times.  To force rereading of a changed module, do this:

   import imp
   import modname
   imp.reload(modname)

Warning: this technique is not 100% fool-proof.  In particular,
modules containing statements like

   from modname import some_objects

will continue to work with the old version of the imported objects.
If the module contains class definitions, existing class instances
will *not* be updated to use the new class definition.  This can
result in the following paradoxical behaviour:

>>> import imp
>>> import cls
>>> c = cls.C()                # Create an instance of C
>>> imp.reload(cls)
<module 'cls' from 'cls.py'>
>>> isinstance(c, cls.C)       # isinstance is false?!?
False

The nature of the problem is made clear if you print out the
"identity" of the class objects:

>>> hex(id(c.__class__))
'0x7352a0'
>>> hex(id(cls.C))
'0x4198d0'
