
``heapq`` --- Heap queue algorithm
**********************************

New in version 2.3.

This module provides an implementation of the heap queue algorithm,
also known as the priority queue algorithm.

Heaps are arrays for which ``heap[k] <= heap[2*k+1]`` and ``heap[k] <=
heap[2*k+2]`` for all *k*, counting elements from zero.  For the sake
of comparison, non-existing elements are considered to be infinite.
The interesting property of a heap is that ``heap[0]`` is always its
smallest element.

The API below differs from textbook heap algorithms in two aspects:
(a) We use zero-based indexing.  This makes the relationship between
the index for a node and the indexes for its children slightly less
obvious, but is more suitable since Python uses zero-based indexing.
(b) Our pop method returns the smallest item, not the largest (called
a "min heap" in textbooks; a "max heap" is more common in texts
because of its suitability for in-place sorting).

These two make it possible to view the heap as a regular Python list
without surprises: ``heap[0]`` is the smallest item, and
``heap.sort()`` maintains the heap invariant!

To create a heap, use a list initialized to ``[]``, or you can
transform a populated list into a heap via function ``heapify()``.

The following functions are provided:

heapq.heappush(heap, item)

   Push the value *item* onto the *heap*, maintaining the heap
   invariant.

heapq.heappop(heap)

   Pop and return the smallest item from the *heap*, maintaining the
   heap invariant.  If the heap is empty, ``IndexError`` is raised.

heapq.heappushpop(heap, item)

   Push *item* on the heap, then pop and return the smallest item from
   the *heap*.  The combined action runs more efficiently than
   ``heappush()`` followed by a separate call to ``heappop()``.

   New in version 2.6.

heapq.heapify(x)

   Transform list *x* into a heap, in-place, in linear time.

heapq.heapreplace(heap, item)

   Pop and return the smallest item from the *heap*, and also push the
   new *item*. The heap size doesn't change. If the heap is empty,
   ``IndexError`` is raised. This is more efficient than ``heappop()``
   followed by  ``heappush()``, and can be more appropriate when using
   a fixed-size heap.  Note that the value returned may be larger than
   *item*!  That constrains reasonable uses of this routine unless
   written as part of a conditional replacement:

      if item > heap[0]:
          item = heapreplace(heap, item)

Example of use:

>>> from heapq import heappush, heappop
>>> heap = []
>>> data = [1, 3, 5, 7, 9, 2, 4, 6, 8, 0]
>>> for item in data:
...     heappush(heap, item)
...
>>> ordered = []
>>> while heap:
...     ordered.append(heappop(heap))
...
>>> print ordered
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> data.sort()
>>> print data == ordered
True

Using a heap to insert items at the correct place in a priority queue:

>>> heap = []
>>> data = [(1, 'J'), (4, 'N'), (3, 'H'), (2, 'O')]
>>> for item in data:
...     heappush(heap, item)
...
>>> while heap:
...     print heappop(heap)[1]
J
O
H
N

The module also offers three general purpose functions based on heaps.

heapq.merge(*iterables)

   Merge multiple sorted inputs into a single sorted output (for
   example, merge timestamped entries from multiple log files).
   Returns an *iterator* over the sorted values.

   Similar to ``sorted(itertools.chain(*iterables))`` but returns an
   iterable, does not pull the data into memory all at once, and
   assumes that each of the input streams is already sorted (smallest
   to largest).

   New in version 2.6.

heapq.nlargest(n, iterable[, key])

   Return a list with the *n* largest elements from the dataset
   defined by *iterable*.  *key*, if provided, specifies a function of
   one argument that is used to extract a comparison key from each
   element in the iterable: ``key=str.lower`` Equivalent to:
   ``sorted(iterable, key=key, reverse=True)[:n]``

   New in version 2.4.

   Changed in version 2.5: Added the optional *key* argument.

heapq.nsmallest(n, iterable[, key])

   Return a list with the *n* smallest elements from the dataset
   defined by *iterable*.  *key*, if provided, specifies a function of
   one argument that is used to extract a comparison key from each
   element in the iterable: ``key=str.lower`` Equivalent to:
   ``sorted(iterable, key=key)[:n]``

   New in version 2.4.

   Changed in version 2.5: Added the optional *key* argument.

The latter two functions perform best for smaller values of *n*.  For
larger values, it is more efficient to use the ``sorted()`` function.
Also, when ``n==1``, it is more efficient to use the built-in
``min()`` and ``max()`` functions.


Theory
======

(This explanation is due to François Pinard.  The Python code for this
module was contributed by Kevin O'Connor.)

Heaps are arrays for which ``a[k] <= a[2*k+1]`` and ``a[k] <=
a[2*k+2]`` for all *k*, counting elements from 0.  For the sake of
comparison, non-existing elements are considered to be infinite.  The
interesting property of a heap is that ``a[0]`` is always its smallest
element.

The strange invariant above is meant to be an efficient memory
representation for a tournament.  The numbers below are *k*, not
``a[k]``:

                                  0

                 1                                 2

         3               4                5               6

     7       8       9       10      11      12      13      14

   15 16   17 18   19 20   21 22   23 24   25 26   27 28   29 30

In the tree above, each cell *k* is topping ``2*k+1`` and ``2*k+2``.
In an usual binary tournament we see in sports, each cell is the
winner over the two cells it tops, and we can trace the winner down
the tree to see all opponents s/he had.  However, in many computer
applications of such tournaments, we do not need to trace the history
of a winner. To be more memory efficient, when a winner is promoted,
we try to replace it by something else at a lower level, and the rule
becomes that a cell and the two cells it tops contain three different
items, but the top cell "wins" over the two topped cells.

If this heap invariant is protected at all time, index 0 is clearly
the overall winner.  The simplest algorithmic way to remove it and
find the "next" winner is to move some loser (let's say cell 30 in the
diagram above) into the 0 position, and then percolate this new 0 down
the tree, exchanging values, until the invariant is re-established.
This is clearly logarithmic on the total number of items in the tree.
By iterating over all items, you get an O(n log n) sort.

A nice feature of this sort is that you can efficiently insert new
items while the sort is going on, provided that the inserted items are
not "better" than the last 0'th element you extracted.  This is
especially useful in simulation contexts, where the tree holds all
incoming events, and the "win" condition means the smallest scheduled
time.  When an event schedule other events for execution, they are
scheduled into the future, so they can easily go into the heap.  So, a
heap is a good structure for implementing schedulers (this is what I
used for my MIDI sequencer :-).

Various structures for implementing schedulers have been extensively
studied, and heaps are good for this, as they are reasonably speedy,
the speed is almost constant, and the worst case is not much different
than the average case. However, there are other representations which
are more efficient overall, yet the worst cases might be terrible.

Heaps are also very useful in big disk sorts.  You most probably all
know that a big sort implies producing "runs" (which are pre-sorted
sequences, which size is usually related to the amount of CPU memory),
followed by a merging passes for these runs, which merging is often
very cleverly organised [1]. It is very important that the initial
sort produces the longest runs possible.  Tournaments are a good way
to that.  If, using all the memory available to hold a tournament, you
replace and percolate items that happen to fit the current run, you'll
produce runs which are twice the size of the memory for random input,
and much better for input fuzzily ordered.

Moreover, if you output the 0'th item on disk and get an input which
may not fit in the current tournament (because the value "wins" over
the last output value), it cannot fit in the heap, so the size of the
heap decreases.  The freed memory could be cleverly reused immediately
for progressively building a second heap, which grows at exactly the
same rate the first heap is melting.  When the first heap completely
vanishes, you switch heaps and start a new run.  Clever and quite
effective!

In a word, heaps are useful memory structures to know.  I use them in
a few applications, and I think it is good to keep a 'heap' module
around. :-)

-[ Footnotes ]-

[1] The disk balancing algorithms which are current, nowadays, are
    more annoying than clever, and this is a consequence of the
    seeking capabilities of the disks. On devices which cannot seek,
    like big tape drives, the story was quite different, and one had
    to be very clever to ensure (far in advance) that each tape
    movement will be the most effective possible (that is, will best
    participate at "progressing" the merge).  Some tapes were even
    able to read backwards, and this was also used to avoid the
    rewinding time. Believe me, real good tape sorts were quite
    spectacular to watch! From all times, sorting has always been a
    Great Art! :-)
